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A) 3:4A body is projectedB) 5:4vertically up. At certain height 'h' above the ground, its PE andC) 9: 25are in the ratio 1:4. Then what height above the ground PE and KE will be in theratio 4:1.D) 4hos with a velocity ofA) h/4B) 5hC) h/5 |
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Answer» PE/KE = ¼ - given 4PE = KE So let at height h' PE and KE are in the ratio 4:1 So for h' : PE/4 = KE PE + KE = constant (PE)h+ (KE)h= (PE)h'+ (KE)h' (PE)h+ (4PE )h= (PE)h'+ ( PE/4)h' (5PE)h= (5/4PE)h' 5mgh = 5/4 mgh' h' = 4h |
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