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A `30kg` block rests on a rough horizontal surface A force of `200N` is applied on the block The block acquires a speed of `4m//s` starting from rest in `2s` What is the value of coefficient of friction ? .A. `(10)/(3)`B. `(sqrt(3))/(10)`C. 0.47D. 0.184 |
Answer» Correct Answer - C ( c) `a=(v)/(t)=(4)/(2)=2ms^(-2) impliesF-f=ma` or `" "200-muxx30xx10=30xx2` `therefore" "mu=0.47` |
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