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a) 3m/s2b) 4m/s2c) 5m/d) OmA cyclist who starts from the top of a hill accelerates uniformly with 0.5 m/storeach the foot with a velocity of 54 kmph. He reaches the foot of the hill ina) 30 sd) 15 sc) 10 Sb) 20 s |
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Answer» Using, v = u + at v = final velocity u = initial velocity t = time taken a = acceleration v = 54 km/hr = 54*5/18 = 3*5 = 15 m/su = 0a = 0.5 m/s^2 15 = 0 + 0.5*tt = 15/0.5t = 150/5 = 30 s Therefore, Cycle reaches foot of the hill in 30 s (a) is correct option |
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