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A 40 kg flywheel in the form of a uniform circular disc 1 m radius is making 120 rpm. Calculate the angularmomentum[251.2 Kgm%) |
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Answer» Mass, m = 40kg Radius, r = 1m Angular velocity is, w = 120 rev/min = (120)(2π)/60 rad/s= 4π rad/s MI of the ring is, I = mr²/2= (40)(1)2kg m2= 40 kg m2 Now, Angular momentum, L = Iw = (40)(4π) = 251.2 kg m2s-1 can you plss explain 2nd step where I=mr2/2 moment of inertia of a disc=mr²/2 then it will be 40×(1)2/2=20 |
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