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`A 40 muF` capacitor in a defibrillator is charged to `3000 V`. The energy stored in the capacitor is sent through the patient during a pulse of duration `2 ms`. The power delivered to the patient isA. `45 kW`B. `180 kW`C. `90 kW`D. `360 kW` |
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Answer» Correct Answer - C A capacitor is a device that stores energy in the electric field between a pair of conductors on which equal but opposite electric charges have been placed. The energy stored in a capacitor `= (1)/(2)CV^(2)` Given, `C = 40muF = 40 xx 10^(-6)F, V = 3000 V` `:. E = (1)/(2) xx 40 xx 10^(-6) xx (3000)^(2) = 180 J` Also `1W = 1 J//s :. 2ms = 2 xx 10^(-3) s` Hence, power `= (180 J)/(2 xx 10^(-3) s)` `= 90 xx 10^(3) W = 90 kW` |
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