Saved Bookmarks
| 1. |
A 4ohm resistance wire id doubled in it,calculate the new resistance? |
|
Answer» Answer: When the wire is doubled the LENGTH will be halved and area will be DOUBLE or TWICE R = PL/A R1 = P(L/2) / 2A Where R1 is the new resistance So R1/R = {P(L/2) / 2A} / {PL/A} When we SOLVE this we get R1/R = ¼ => R1 = R/4 = 4/4 = 1 OHM |
|