1.

A 75 watt bulb draws 680 mA how much time will be required to pass 30 columb change through the bulb

Answer»

tion:P = 75W I = 680 mA = 680/1000 A Q = 30 coulombs P = VI => V = 75 x 1000 / 680 => V = 110V ( ROUNDED off) W = qV = 30 x 110= 3300J T = W/P= 3300 / 75= 44 seconds ( approx) Or you can directly do it this way :-t = q/I= 30 x 1000 / 680= 44 seconds ( approx)



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