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A 8000 kg engine pulls a trainof 5 wagons, each of 2000 kg along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate (a) The net accelerating force (b) The acceleration of the train (c ) The force ofwagon 1 on wagon 2. |
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Answer» Solution :FORCE EXERTED by the engine, F=40000N. Frictional force offered by the track `F_f=5000N`.Net accelerating force ,`Fa=F-F_f` =40000-5000 =-35000N Hence , the net accelerating force is 35000N . Acceleration of the train =a The engine exerts a force of 40000N on all the five wagons. Net acceleration force on the wagons=Fa=35000N Mass of the wagons, m=Mass of a wagon X number of wagons Mass of a wagon =5 `m 2000xx5 =10000 kg` Total mass M=m=10000 kg From Newton.s second LAW of MOTION `F_a=M_a` `a=F_(am)=[35000xx1000=3.5 ms^(2)]` Hence the acceleration of the wagons and the train is `3.5 m//s^2` Mass of all the wagons except wagon 1 is `4 xx 2000 =8000 kg` Acceleration of the wagons `=3.5 m//s^2` Thus , force exerted on all the wagons except wagon 1 `=8000 xx3.5 =28000 N` Therefore , the force exerted by wagon 1 on the remaining four wagons is 28000N,. Hence , the force exerted by wagon 1 on Wagon 2 is 28000 N. |
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