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For a given glass prism, as the angle of incidence increases, theangle of emergence __________ . |
Answer» decreases `(SIN i_(1))/(sin r_(1)) = (sin i_(2))/(sin r_(2)) = mu`(1) Where `i_(1) and r_(1)` are angle of incidence and refraction at the firstrefracting surface, `i_(2) and r_(2)` are angle of incidence andrefraction at SECOND refracting surface from (1) we can write `(sin i_(1))/(sin r_(1)) = mu` As `mu` of the material of the prism remains constant with increase in angle of incidence `i_(1)` angle of refraction `r_(1)` ALSO increases. Now, `A = r_(1) + r_(2)` But for a given prism, A remains constant `:. r_(1) + r_(2)` = constant. In theabove equation, if `r_(1)` increases due to increase in `i_(1) ` then `r_(2)`must decrease. With decrease in `r_(2)`, angle of EMERGENCE decreases, as ` mu = (sin i_(2))/(sin r_(2))` |
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