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A `A={3,6,9,12,15,18,21},B={4,6,12,16,20},C={2,4,6,8,10,12,14,16},D={15,10,15,20}`, Find : (i) `A - B` (ii) `A-C` (iii) `A-D` (iv) `B-A` (v) `C-A` (vi) `D-A` (vii) `B-C` (viii) `B-D` (ix) `C-B` (x) `D-B` (xi) `C-D` (xii) `D-C`. |
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Answer» (i) `A={3,6,9,12,15,18,21} andB={4,8,12,16,20}` `A-B={x:x in A" but "x cancel(in)B}` `={3,6,9,15,18,21}` Therefore, `A-B={3,6,9,15,18,21}` (ii) `A={3,6,9,12,15,18,21}` and `C={2,4,6,8,10,12,14,16}` `A-C={x:x in A " but " x cancel(in)C}` Therefore, `A-C={3,9,15,18,21}` (iii) `A={3,6,9,12,15,18,21} and {5,10,15,20}` `A-D={x:x in A " but "x cancel(in)D}` Therefore, `A-D={3,6,9,12,18,21}` (iv) `A={3,6,9,12,15,18,12}` and `B={4,8,12,16,20}` `B-A={x:x in B" but "x cancel(in)A}` `={4,8,16,20}` Therefore, `B-A={4,8,16,20}` (v) `A={3,6,9,12,15,18,21}` and `D={5,10,15,20}` `:. D-A={x:x in D " but "x cancel(in)A}` `={5,10,20}` Therefore, `D-A = {55,10,20}` (vii) `B={4,8,12,16,20} and C={2,4,6,8,10,12,16}` `B-C={x:x in B" but "x cancel(in)C}` `= {2}` Therefore, `B-C = {20}` (viii) `B={4,8,12,16,20}and D={5,10,15,20}` `B-D={x:x in B" but "x cancel(in)D}` `={4,8,12,16}` Therefore, `B-D = {4,8,12,16}` (ix) `B={4,8,12,16,20}and C={2,4,6,8,10,12,14,16}` `C-B={x:x in C" but "x cancel(in)B}` `={2,6,10,14}` Therefore, `C-B = {2,6,10,14}` (x) `B={4,8,12,16,20}andD={5,10,15,20}` `D-B={x:x in D " but "x cancel(in)B}` `={5,10,15}` Therefore, `D-B = {5,10,15}` (xi) `C={2,4,6,8,10,12,14,16} and D={5,10,15,20}` `C-D={x:x in C " but "x cancel(in)D}` `={2,4,6,8,12,14,16}` Therefore, `C-D = {2,4,6,8,12,14,16}` (xii) `C={2,4,6,8,10,12,14,16} andD={5,10,15,20}` `:. D-C={x:x in D " but "x cancel(in)C}` `={5,15,20}` Therefore, `D-C={5,15,20}`. |
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