1.

.(a) A bus increases its speed from 36 km/h to 72 km/h in 10 seconds calculate its acceleration. (2) (b) Using Graphical method solve position - time relation. (3)

Answer»

EXPLANATION:

A) We have

u = 36 km/h

= 10 m/s

v = 72 km/h

= 72× 100 / 60 × 60

= 7200/ 360

= 20 m/s

t = 10 second

We know

A = V- U / t

= 20 - 10 / 10

= 1 m/s ^2

Hence the ACCELERATION of the bus after increasing it's speed is 1 m/s^2



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