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.(a) A bus increases its speed from 36 km/h to 72 km/h in 10 seconds calculate its acceleration. (2) (b) Using Graphical method solve position - time relation. (3) |
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Answer» A) We have u = 36 km/h = 10 m/s v = 72 km/h = 72× 100 / 60 × 60 = 7200/ 360 = 20 m/s t = 10 second We know A = V- U / t = 20 - 10 / 10 = 1 m/s ^2 Hence the ACCELERATION of the bus after increasing it's speed is 1 m/s^2
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