a A farmer moves along theboundany ofn square ietd of sicde10 m in 40

1.	a A farmer moves along theboundany ofn square ietd of sicde10 m in 40 s. Whar will be themognitude of desplocement of theJarmer at the end of 2 minutes 20seconds from his nitial postion?
Answer» Total distance 40m in 40 sec. Total time taken by the farmer = 2 min 20 sec =140 seconds. Total rounds completed= 140/40=3.5 rounds That means if the farmer starts from point A of the square field, he reaches point C. Therefore, displacement is AC. Assume ABC is a right angled triangle. Therefore,AC^2= AB^2+BC^2AC^2 = (10)^2+(10)^2 AC^2= 100+100 AC^2=200 AC = (200)^1/2 AC= 10× (2)^½

a A farmer moves along theboundany ofn square ietd of sicde10 m in 40 s. Whar will be themognitude of desplocement of theJarmer at the end of 2 minutes 20seconds from his nitial postion?

Answer»

Total distance 40m in 40 sec.

Total time taken by the farmer

= 2 min 20 sec =140 seconds.

Total rounds completed= 140/40=3.5 rounds

That means if the farmer starts from point A of the square field, he reaches point C.

Therefore, displacement is AC.

Assume ABC is a right angled triangle.

Therefore,AC^2= AB^2+BC^2AC^2

= (10)^2+(10)^2

AC^2= 100+100

AC^2=200

AC = (200)^1/2

AC= 10× (2)^½

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a A farmer moves along theboundany ofn square ietd of sicde10 m in 40 s. Whar will be themognitude of desplocement of theJarmer at the end of 2 minutes 20seconds from his nitial postion?

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