InterviewSolution
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InterviewSolution
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(a) A liquid mixture of benzene and toluene is composed of `1` mol of benzene and `1` mol of tolune if the pressure over the mixture at `300K` is reduced, at what pressure does the first bubble form? (b) What is the composition of the first bubble formed. (c) If the pressure is reduced further, at what pressure does the last trace of liquid disapper? (d) What is the composition of the last drop of liquid? (e) What will be the pressure, composition of the liquid and the composition of vapour, when `1` mol the mixture has been vaporized? Given `P_(T^(0))=40mmHg, P_(B^(0))=100mmHg` |
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Answer» Correct Answer - (a) `70 mmHg,` (b) `X_(b)=5//7` (c) `P=400//7=57.14 mm` (a) `P=X_(A)P_(A)+X_(B)P_(B)^(0)=0.5xx40+0.5xx100=70` (b) `Y_(A)=(0.5xx40)/(70)=(2)/(7) , Y_(B)=(5)/(7)` ltbRgt (c ) at last trace of liquid `Y_(A)=0.5 , Y_(B)=0.5` `(1)/(P)=(Y_(A))/(P_(A)^(0))+(Y_(B))/(P_(B)^(0))=(0.5)/(40)+(0.5)/(100)` `P=(400)/(7)` (d) `Y_(A)=(Y_(A)P_(A)^(0))/(P) rArr0.5=(X_(A)40)/(400//7) , X_(A)=(5)/(7) , X_(B)=(2)/(7)` (e) Let `X` mole of `B` be present in liquid phase. `{:(,"Mole ofA","Mole of B"),("Liquid",1-x,x),("Vapour",x,1-x):}` `P=40(1-x)+100 x` `(1)/(P)=(Y_(A))/(P_(A)^(0))+(Y_(A))/(P_(B))rArr(1)/(P)=(x)/(40)+(1+x)/(100)=(100x+(1-x)40)/(40xx100)` So `p^(2)=40xx100` `p=20sqrt(10)` `20sqrt(10)=40(1-x)+100x=40+60x` `x=(20sqrt(10)-10)/(60)=(sqrt(10)-2)/(3)` |
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