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a. A myopic person can see the objects up to 2m from the eye Calculate power of thecorrective lens to be used to correct this defect of vision |
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Answer» Given distance of far point (D) = 2m Let f be the focal length of eye lens. Image distance (distance between eye lens and retina ) for our human eye is always constant and is about 2.5 cm.This is due to the action of ciliary muscles. Applying lens formula, we get f = -D = -2 cm but, the power of a lens is reciprocal of focal length.hence. Power = 1/f (f in meters)= 1/-2= - 0.5 dioptre. |
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