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A alone can do a work in 20 days. B is 25% more efficient than A. A and B started working and worked for 4 days. If C alone completed the remaining job in 22 days. How many days C alone takes to complete the entire job?1). 24 days2). 36 days3). 12 days4). 20 days |
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Answer» A alone can do work in 20 days. B is 25% more efficient than A. ⇒ B can do a work in 16 days. Let the total UNIT of work ( LCM of 20 and 16) = 80 UNITS ⇒ A’s one day work = 4 ⇒ B’s one day work = 5 As A and B left after working for 4 days. ⇒ Work done by A and B in 4 days = 36 work ⇒ Work left = 44 units is done by C in 22 days. ⇒ C’s one day work = 2 units ∴ 80 units of work can be completed by C alone in 80/2 = 40 days |
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