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A tank can be filled using pipe A and emptied using pipe B. Pipe B can empty the tank in 12 hrs. When both the pipes are simultaneously opened, the tank is half full in 2 hrs. In how much time can pipe A fill the tank alone?1). 2 hrs.2). 3 hrs.3). 4 hrs.4). 6 hrs. |
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Answer» Let pipe A can fill the tank in ‘X’ HOURS B’s 1 hr. work = 1/12 When both are opened SIMULTANEOUSLY, work done in 2 hours, ⇒ (1/x – 1/12) × 2 = 1/2 ⇒ (1/x – 1/12) = 1/4 ⇒ 1/x = 1/4 + 1/12 ⇒ 1/x = 1/3 ⇒ x = 3 hrs. ∴ Pipe A can fill the tank alone in 3 hours |
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