1.

A tank can be filled using pipe A and emptied using pipe B. Pipe B can empty the tank in 12 hrs. When both the pipes are simultaneously opened, the tank is half full in 2 hrs. In how much time can pipe A fill the tank alone?1). 2 hrs.2). 3 hrs.3). 4 hrs.4). 6 hrs.

Answer»

Let pipe A can fill the tank in ‘XHOURS

A’s 1 HR. WORK = 1/x

B’s 1 hr. work = 1/12

When both are opened SIMULTANEOUSLY, work done in 2 hours,

⇒ (1/x – 1/12) × 2 = 1/2

⇒ (1/x – 1/12) = 1/4

⇒ 1/x = 1/4 + 1/12

⇒ 1/x = 1/3

⇒ x = 3 hrs.

∴ Pipe A can fill the tank alone in 3 hours


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