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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A can do a work in 9 days, if B is 50 % more efficient than A, then in how many days can B do the same work ?1). 13.5 days2). 4.5 days3). 6 days4). 3 days |
| Answer» HELLO, 6 DAYS is CORRECT | |
| 2. |
10 men working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the same work in 12 days ?1). 6 days2). 10 days3). 12 days4). 15 days |
| Answer» 6 DAYS : - OPTION 1 | |
| 3. |
1). 5 hrs2). 8 hrs3). 6 hrs4). 9 hrs |
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Answer» ∴ In 1 HOUR X can do = 1/15 ∴ In 5 hours X can do = 5/15 = 1/3 ∴Remaining work = 1 – 1/3 = 2/3 In 5 hours y can do = 2/3 ∴In 1 hour Y can do = 2/15 Let, they together complete the work in = a hour According to the problem, $( \Rightarrow \;a\LEFT( {\frac{1}{{15}} + \frac{2}{{15}}} \right) = 1)$ $( \Rightarrow \;a\left( {\frac{{1 + 2}}{{15}}} \right) = \;1)$ $( \Rightarrow \;a\;\left( {\frac{3}{{15}}} \right) = 1)$ $( \Rightarrow \;a = \;\frac{{15}}{3})$ $( \Rightarrow \;a = 5)$ ∴ They together complete the work in 5 hours. |
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| 4. |
6 men and 8 women can do a work in 10 days. Then 3 men and 4 women can do the same work in1). 24 days2). 20 days3). 12 days4). 18 days |
| Answer» OPTION 2 : 20 DAYS is CORRECT | |
| 5. |
A and B together can do a piece of work in 10 days. A alone can do it in 30 days. The time in which B alone can do it is1). 10 days2). 12 days3). 15 days4). 20 days |
| Answer» OPTION 3 is the RIGHT ANSWER | |
| 6. |
Two workers Anushka and Kriya working together completed a job in 4 days. If Anushka worked two-third times as efficiently as she actually did and Kriya worked one-sixth as efficiently as she actually did, the work would have been completed in 8 days. To complete the job alone, Anushka would require1). 12 days2). 6 days3). 8 days4). 9 days |
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Answer» Let number of DAYS needed by ANUSHKA and Kriya to finish the work be x and y respectively. ∴ part of work done by Anushka in one day = 1/x And part of work done by Kriya in one day = 1/y ∴ Part of work done by both of them working together $(= \;\frac{1}{x} + \frac{1}{y} = \frac{1}{4})$-------(i) According to the question, if Anushka worked (2/3) as efficiently as she actually did, Part of work done by Anushka in one day = 2/3x Also, Kriya worked (1/6) as efficiently as she actually did, ∴ Part od work FINISHED by Kriya in one day = 1/6y In this case, the work would have been completed in 8 days. $(\therefore \frac{2}{{3x}} + \frac{1}{{6y}} = \frac{1}{8})$---------(II) Solving equation (i) and (ii) simultaneously, we get ⇒ x = 6 ∴ Anushka would require 6 days to complete the job alone. |
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| 7. |
A tank can be filled using pipe A and emptied using pipe B. Pipe B can empty the tank in 12 hrs. When both the pipes are simultaneously opened, the tank is half full in 2 hrs. In how much time can pipe A fill the tank alone?1). 2 hrs.2). 3 hrs.3). 4 hrs.4). 6 hrs. |
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Answer» Let pipe A can fill the tank in ‘X’ HOURS B’s 1 hr. work = 1/12 When both are opened SIMULTANEOUSLY, work done in 2 hours, ⇒ (1/x – 1/12) × 2 = 1/2 ⇒ (1/x – 1/12) = 1/4 ⇒ 1/x = 1/4 + 1/12 ⇒ 1/x = 1/3 ⇒ x = 3 hrs. ∴ Pipe A can fill the tank alone in 3 hours |
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| 8. |
1). 652). 723). 454). 60 |
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Answer» A PIPE can fill the tank in = 10 hours ∴ In 1 hour pipe can fill = 1/10 Tank is ACTUALLY filled in = 12 hours ∴ In 1 hour tank actually fills = 1/12 ∴ In 1 hour the leak empties, $( \Rightarrow \frac{1}{{10}} - \frac{1}{{12}})$ $( \Rightarrow \frac{{6 - 5}}{{60}})$ ⇒ 1/60 ∴ The leak can empty the WHOLE tank in = 60 hours |
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| 9. |
1). 1602). 1503). 1304). 175 |
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Answer» WORK done by MEN in one day = 1/80 Work done by 12 men in one day = 12/80 Work done by 12 men and 16 women in one day = 1/4 ∴ Work done by 16 women in one day = 1/4 - 12/80 = 1/10 Work done by one women in one day = 1/10 × 1/16 = 1/160 ∴ 160 days are required for one women alone to COMPLETE the same work |
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| 10. |
A can do a piece of work in 12 days while B alone can do it in 15 days. With the help of C they can finish it in 5 days. If they are paid Rs. 960 for the whole work how much money A gets?1). Rs. 4802). Rs. 2403). Rs. 3204). Rs. 400 |
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Answer» Concept: $(\FRAC{1}{a}:\frac{1}{b}:\frac{1}{c} = \frac{{LCM\;of\;\left( {a,b,c} \right)}}{a}:\frac{{LCM\;of\;\left( {a,b,c} \right)}}{b}:\frac{{\left( {LCM\;of\;\left( {a,b,c} \right)} \right)}}{c})$ A can do a PIECE of work in 12 days. ∴ Part of work done by A in 1 day = 1/12 B can do a piece of work in 15 days ∴ Part of work done by B in 1 day = 1/15 Let, C can do a piece of work in ‘x’ days ∴ Part of work done by C in 1 day = 1/x ? A, B and C can do the work in 5 days $(\THEREFORE \frac{1}{{12}} \times 5 + \frac{1}{{15}} \times 5 + \frac{1}{x} \times 5 = 1)$ $(\Rightarrow \frac{5}{{12}} + \frac{1}{3} + \frac{5}{x} = 1)$ ⇒ (9/12) + (5/x) = 1 ⇒ 5/x = 1 – (9/12) ⇒ 5/x = 3/12 ⇒ x = 20 ∴ Part of work done by C in 1 day = 1/20 ∴ Ratio of part of work done by A, B and C = 1/12 : 1/15 : 1/20 ? LCM of 12, 15 and 20 is 60. = (1/12) × 60 : (1/15) × 60 : (1/20) × 60 = 5 : 4 : 3 ∴ Ratio of money A, B and C get = 5 : 4 : 3 Given, Total money got by A, B and C together = Rs. 960 ∴ Money A gets = {5/(5 + 4 + 3)} × 960 = (5/12) × 960 = Rs. 400 |
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| 11. |
If A, B and C together do a job in 4 days, A and C together do the job in 4.5 days and B and C together do the job in 12 days, then in how many days can C alone do the job?1). 362). 63). 184). 12 |
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Answer» We have, EFFICIENCY of (A + B + C) : (B + C) : (C + A) = (1/4) : (1/4.5) : (1/12) = 9 : 8 : 3 ⇒ Efficiency of C = efficiency of {(A + C) + (B + C) - (A + B + C)} = 8 + 3 - 9 = 2 ⇒ (Efficiency of A + B + C) / (Efficiency of C) = (Time taken by C) / (Time taken by A + B) ⇒ 9/2 = (Time taken by C)/4 ∴ Time taken by C = 18 days |
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| 12. |
Meena and Sanju can complete a work in 32 days and 48 days respectively. Both of them started working together but after some days Meena left the work and Sanju alone completed the work in 24 days. For how many days did Meena work?1). \(9\frac{3}{5}\) days2). \(4\frac{3}{5}\) days3). \(5\frac{1}{5}\) days4). \(5\frac{3}{5}\) days |
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Answer» Let the TOTAL work be 96 units Efficiency of Meena = 96/32 = 3 units/day Efficiency of Sanju = 96/48 = 2 units/day Suppose Meena and Sanju worked together for x days Worked done by them = 5x Remaining work = 96 – 5x Now, this work is completed by Sanju in 24 days According to the QUESTION, ⇒ 2 = (96 – 5x) /24 ⇒ 48 = 96 – 5x ⇒ 48 = 5x $(\Rightarrow \;x = \frac{{48}}{5} = 9\frac{3}{5})$ ∴ Meena LEFT the work after $(9\frac{3}{5})$ days |
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| 13. |
B would have taken 10 hours more than what A would have taken to complete a task if each of them worked alone. Working together they can complete the task in 12 hours. How many hours would B take to do 50% of the task?1). 302). 153). 204). 10 |
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Answer» Let A would have taken x hours to complete the task, ⇒ According to given CONDITION B would take (x + 10) hours to complete the task ⇒ WORK done in one day by A and B will be 1/x and 1/(x + 10) units Since working together they take 12 hours to complete the task, ⇒ 1/x + 1/(x + 10) = 1/12 ⇒ (2x + 10)/(x2 + 10x) = 1/12 ⇒ 24x + 120 = x2 + 10x ⇒ x2 - 14x - 120 = 0 ⇒ (x - 20) (x + 6) = 0 ⇒ x = 20, -6 ∴ B will take 30 hours to complete the task and 15 hours to complete 50% task. |
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| 14. |
A can do $\frac{1}{4}$ of a work in 10 days. B can do $\frac{1}{3}$ of the work in 20 days. In how many days can both A and B together do the work ?1). 30 days2). 32 days3). 24 days4). 25 days |
| Answer» | |
| 15. |
A can finish a work in 24 days. B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in :1). 5 days2). 6 days3). 10 days4). $10\frac{1}{2}$ days |
| Answer» 10 DAYS | |
| 16. |
A B and C can do a pieceof work in24, 30 and 40 days respectively. They began the work together but C left 4 days before completion of the work. In how many days was the work done ?1). 132). 123). 144). 11 |
| Answer» 11 : - OPTION 4 | |
| 17. |
A does 20% less work than B. if A can complete a piece of work in $7\frac{1}{2}$ hours, then B can do it in1). $6\frac{1}{2}$ hours2). 6 hours3). $5\frac{1}{2}$ hours4). 5 hours |
| Answer» | |
| 18. |
A does half as much work as B in one-third of the time taken by B. If together they take 10 days to complete a work, then the time taken by B alone to do it would have been1). 30 days2). 25 days3). 6 days4). 12 days |
| Answer» OPTION 2 is the ANSWER | |
| 19. |
A takes twice as much time as B and thrice as much as C to complete a piece of work . They together complete the work in 1 day. In what time,will A alone complete the work.1). 9 days2). 5 days3). 6 days4). 4 days |
| Answer» OPTION option 3 is the CORRECT ANSWER | |
| 20. |
A, B and C together can do a piece of work in 40 days. After working with B and C for 16 days. A leaves and then B and c complete the remaining work in 40 days more. A alone could do the work in1). 80 days2). 90 days3). 100 days4). 120 days |
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Answer» it from PREVIOUS year ssc papers, 100 DAYS is the RIGHT ANSWER |
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| 21. |
45 men can complete a work in 16 days. Four days after they started working. 36 more men joined them. How many days will they now take to complete the re- maining work ?1). 6 days2). 8 days3). $6\frac{2}{3}$ days4). $7\frac{3}{4}$ days |
| Answer» | |
| 22. |
If 72 men can build a wall of 280 m length in 21 days, how many men could take 18 days to build a similarr type of wall of length 100 m ?1). 302). 103). 184). 28 |
| Answer» 30 is the ANSWER | |
| 23. |
If 4 men or 8 women can do a piece of work in 15 days, in how many days can 6 men and 12 women do the same piece of work ?1). 20 days2). 45 days3). 15 days4). 30 days |
| Answer» | |
| 24. |
A and B together can complete a job in 8 days. Both B and C, working alone can finish the same job in 12 days. A and B commence work on the job. and work for 4 days, where upon A leaves. B continues for 2 more days, and then he leaves too. C now starts working, and finishes the Job. How many days did C require ?1). 52). 83). 34). 4 |
| Answer» | |
| 25. |
A certain number of men can do a piece of work in 45 days. If there were 6 men more, the work can be finished 18 days earlier. The number of men working is1). 62). 93). 124). 15 |
| Answer» | |
| 26. |
3 men or 4 women can complete a job in 120 days. 12 men and 16 women will complete the same job in how many days?1). 122). 143). 154). 18 |
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Answer» Given: 3 men or 4 women completes a work in 120 days ⇒ TIME TAKEN by 12 men to complete the work = (120/12) × 3 = 30 days ⇒ Time taken by 16 women to complete the work = (120/16) × 4 = 30 days ⇒ Time taken by 12 men and 16 women to complete the work = 1/[(1/30) + (1/30)] ⇒ Time taken by 12 men and 16 women to complete the work = 15 days ∴ the correct option is 3) |
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| 27. |
1). 62). 93). 44). 10 |
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Answer» Let Z can do a work in z days. ⇒ Z will do 1/z amount of work in 1 day. ⇒ X and Y will do 1/10 and 1/15 amount of work in 1 day. ⇒ Total work done by all three in 1 day = 1/3 ⇒ $(\frac{1}{{10}} + \frac{1}{{15}} + \frac{1}{z} = \frac{1}{3})$ ⇒ $(\frac{1}{z} = \frac{1}{3} - \frac{1}{{10}} - \frac{1}{{15}} = \frac{{10 - 3 - 2}}{{30}} = \frac{5}{{30}} = \frac{1}{6})$ ∴ Z will take 6 days to complete the work alone. |
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| 28. |
Two inlet pipes A & C can fill a tank in 10 hours & 20 hours respectively, operating alone. Outlet pipe B can empty a full tank in 8 hours. Pipe A discharge milk. Whereas pipe C discharges water. The 3 pipes are opened in the order, A, C, C, B, C, A, B. i.e. only pipe A is opened for 1st hour, then only pipe C is opened for the 2nd hour and so on. This continues for 7 hours. Find the ratio of milk to water in the tank after 7 hours.1). 7 : 52). 5 : 73). 11 : 74). 7 : 11 |
| Answer» | |
| 29. |
A can do a piece of work in 25 days and B can do the same work in 30 days. They work together for 5 days, how much of work is left ?1). $\frac{11}{30}$2). $\frac{15}{30}$3). $\frac{19}{30}$4). $\frac{12}{30}$ |
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Answer» it from previous YEAR ssc papers, $\frac{19}{30}$ is the RIGHT answer |
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| 30. |
Raja can do a piece of work in 20 days while Ramesh can finish it in 25 days. Ramesh started working and Raja joined him after 10 days. The whole work is completed in1). 18 days2). $16\frac{2}{3}$ days3). 20 days4). 15 days |
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Answer» $\LARGE 16\frac{2}{3}$ days is correct Let the total work is $\large 100$ UNITS. Raja in a DAY can do $\large5$ units. Ramesh in a day can do $\large 4$ units. Both TOGETHER can do $\large 9$ units work in a day. Hence In 1st $\large 10$ days ramesh FINISHED $\large 40$ units of work alone. $\large 60 $ units of work will be completed by both of them together. Hence No. of days $\large = \frac{60}{9} + 10 $ $ \large =\frac{50}{3}$ $ \large = 16 \frac{2}{3}$ |
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| 31. |
A is 30% more efficient than B, and can alone do a work in 23 days. The number of days, in which A and B, working together can finish the Job is1). 11 days2). 13 days3). 20 days4). 21 days |
| Answer» 13 DAYS is the ANSWER | |
| 32. |
30 persons can finish a job in 20 days. After 6 days, how many persons should leave the job, so that work is completed in a total of 26 days?1). 92). 123). 84). 7 |
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Answer» 30 PERSONS can finish a job in 20 days, ⇒ Total work = Days × men = 20 × 30 = 600 units Work DONE in 6 days by 30 men = 6 × 30 = 180 units ⇒ Remaining work = 420 units As the work is completed in a total of 26 days, ⇒ Remaining 420 units work to be completed in 20 days, ⇒ No of men = 420/20 = 21 men ∴ 9 men should leave. |
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| 33. |
3 men or 5 women can do a work in 12 days. How long will 6 men and 5 women take to finish the work?1). 20 days2). 10 days3). 4 days4). 15 days |
| Answer» | |
| 34. |
12 men or 30 boys can complete a work in 72 days. How many days will 48 men and 24 boys will take to complete the same work?1). 202). 183). 154). 25 |
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Answer» We have, Efficiency of 12 men = Efficiency of 30 boys ⇒ Efficiency of 2 men = Efficiency of 5 boys ⇒ Efficiency of 48 men = Efficiency of 120 boys Now, we have of find out time taken by 48 men and 24 boys to complete the work or 144(120 + 24) boys to complete the works Now, Total work = time taken × NUMBER of WORKERS = 72 × 30 = 2160 ⇒ Time taken by 144 boys to complete the work = Total work/no. of workers = 2160/144 = 15 DAYS ∴ 48 men and 24 boys TAKE 15 days to complete the work |
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| 35. |
A and B together can do a piece of work in 12 days, while B alone can finish it in 30 days. A alone can finish the work in1). 20 days2). 25 days3). 15 days4). 18 days |
| Answer» 20 days is the CORRECT ANSWER as per the SSC answer key | |
| 36. |
A contractor undertook to do a piece of work in 12 days. He employed certain number of labours, about 3 of them being absent from the very first day, the rest could finish the work in 18 days. Find the number of men originally employed?1). 152). 63). 134). 9 |
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Answer» Let X be the NUMBER of LABOURS employed initially and Y be the work done by each labour in one day But as 3 of the labours absent and the work was done by the remaining in 18 days Hence the work done initially by X labours in 12 days will be equal to the work done after the 3 labours are gone. ⇒ 12XY = 18(X - 3) Y ⇒ 12X = 18X - 54 ⇒ 6X = 54 ∴ X = 9 |
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| 37. |
If 5 men or 8 women can do a piece of work in 12 days, how many days will be taken by 2 men and 4 women to do the same work ?1). 15 days2). $13\frac{1}{2}$ days3). $13\frac{1}{3}$ days4). 10 days |
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Answer» it from previous YEAR ssc papers, $13\frac{1}{3}$ days is the RIGHT ANSWER |
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| 38. |
If A and B together can complete a work in 18 days, A and C together in 12 days and B and C together in 9 days, then B alone can do the work in1). 18 days2). 24 days3). 30 days4). 40 days |
| Answer» OPTION 2 : 24 DAYS is CORRECT | |
| 39. |
Two workers A and B are engaged to do a piece of work. A working alone would take 8 hours more to complete the work than when work together. If B worked alone, would take $4\frac{1}{2}$ hours more than when work together. The time required to finish the work together is1). 5 hours2). 4 hours3). 8 hours4). 6 hours |
| Answer» OPTION option 4 is the CORRECT ANSWER | |
| 40. |
When A and B work together they take 20 days to complete the piece of work. When A works alone he takes 28 days. B gets a share of Rs. 600 when they work together. What is the total amount they receive?1). Rs. 1,5002). Rs. 1,6003). Rs. 1,8004). Rs. 2,100 |
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Answer» A’s one day’s WORK $(= \frac{1}{{28}})$ A and B’s one day’s work $(= \frac{1}{{20}})$ B’s one day’s work $(= \frac{1}{{20}} - \frac{1}{{28}} = \frac{1}{{70}})$ (A’s one day’s work) ? (B’s one day’s work) $(= \frac{1}{{28}}:\frac{1}{{70}} = 5:2)$ B’s share is Rs. 600 Let 5x, 2x be A and B’s share. ∴ 2x = 600 ∴ x = 300 A’s share = 5x = Rs. 1,500 Total share = 1500 + 600 = Rs. 2,100 |
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| 41. |
A does 25% less work than B. If A can complete a piece of work in 7½ hours then B can do it in1). 5.625 hours2). 6 hours3). 4.625 hours4). 5 hours |
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Answer» A takes $(\frac{{15}}{2}\;)$hours to COMPLETE the work ∴ Work done by A in one HOUR = 2/15 Let B TAKE ‘x’ hours to complete the work ∴ Work done by B in 1 hour = 1/x ∴ According to the given condition, $(\begin{array}{l} \frac{1}{x} - 0.25 \times \LEFT( {\frac{1}{x}} \right) = \;\frac{2}{{15}}\\ \therefore \;\frac{1}{x}\; \times \left( {1 - \;\frac{1}{4}} \right) = \;\frac{2}{{15}} \END{array})$ ∴ 2x/15 = 3/4 ∴ x = 5.625 ∴ B can complete the work in 5.625 hours. |
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| 42. |
1). 12 days2). 6 days3). 3 days4). 24 days |
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Answer» Time taken by PANNALAL to do the job = 20/(1/3) = 60 DAYS Time taken by Sai Prasad to do the job = 10/(2/3) = 15 days ∴ Time taken by both Pannalal and Sai Prasad together to do the job = 1/(1/15 + 1/60) = 12 days |
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| 43. |
P and Q undertook to do a work for Rs. 7200. P alone could do it in 20 days and Q alone in 12 days. With the assistance of R they finished the work in 5 days. What is the share (in Rs) of R?1). 18002). 24003). 28004). 2600 |
| Answer» | |
| 44. |
4 men and 6 women get Rs. 2400 by doing a piece of work in 5 days. 3 men and 7 women get Rs. 2760 by doing the same work in 6 days. In how many days, 7 men and 6 women can complete the same work getting Rs. 5280?1). 6 days2). 8 days3). 10 days4). 12 days |
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Answer» LET the daily wage of 1 man and 1 WOMEN be a and b respectively. Given, 4 men and 6 women get Rs. 2400 by doing a piece of work in 5 days. ∴ 4a + 6b = 2400/5 = 480 Also, 3 men and 7 women get Rs. 2760 by doing the same work in 6 days. ∴ 3a + 7b = 2760/6 = 460 On solving these two equation, we get a = 60, b = 40. Let the number of days for which 7 men and 6 women have to work so that they get Rs. 5280 be d days. ⇒ 7 × 60 + 6 × 40 = 5280/d ⇒ 660 = 5280/d ⇒ d = 8 days |
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| 45. |
A can do a piece of work in 20 days and B can do the same piece of work in 30 days. Find in how many days both can do the work ?1). 16 days2). 14 days3). 10 days4). 12 days |
| Answer» 12 DAYS is the ANSWER | |
| 46. |
A and B can together finish work in 30 days. They worked at it for 20 days and then B left. The remaining work was done by A alone in 20 more daysA alone can finish the work in1). 60 days2). 54 days3). 48 days4). 50 days |
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| 47. |
One man or two women or three boys can do a piece of work in 88 days. One man, one woman and one boy will do it in1). 44 days2). 24 days3). 48 days4). 20 days |
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| 48. |
A, B and C undertook a work for Rs. 80000. Together A and B complete 3/4th part of the work. What is the share (in Rs.) of C?1). 200002). 250003). 300004). 22000 |
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Answer» A, B and C undertook a work for Rs. 80000. A and B complete (3/4th) PART of the work. Remaining work = 1- (3/4) = 1/4 The share of $(C = \FRAC{1}{4} \times 80000 = Rs.\;20000)$ |
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| 49. |
A, Band C can complete a work in 10, 12 and 15 days respectively. They started the work together. But A left the work before 5 days of its completion. B also left the work 2 days after A left. In how many days was the work completed?1). 4 days2). 5 days3). 7 days4). 8 days |
| Answer» ANSWER for this QUESTION is 7 DAYS | |
| 50. |
1). 102). 123). 154). 8 |
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Answer» Let, No. of men initially = x x men can COMPLETE the work in 10 days. ∴ Total work = 10x Work done in 4 days = 4X ∴ Remaining work = 10x – 4x = 6x According to problem, (x – 6) COMPLETED the remaining work in = 12 days ∴ 12(x – 6) = 6x ⇒ 6x = 72 ⇒ x = 12 ∴ Initially there were 12 men. |
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