InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 301. |
One man, 3 women and 4 boys can do a piece of work in 96 hours, 2 men and 8 boys can do it in 80 hours, 2 men and 3 women can do it in 120 hours. 5 men and 12 boys can do it in1). $39\frac{1}{11}$ hours2). $42\frac{7}{11}$ hours3). $43\frac{7}{11}$ hours4). 44 hours |
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| 302. |
A swimming pool has 3 pipes to drain off the water. The first two pipes A and B, operating simultaneously, can empty the pool in 9/16 the time than that taken by C alone. Pipe A, working alone, takes one third the time taken by pipe B. All of them together take 2 hrs 24 minutes to empty the pool. Time taken by pipe A to empty the pool in hours is1). 52). 103). 154). 20 |
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Answer» Let the efficiencies of the THREE pipes be a, b and c. As the first two pipes A and B OPERATING simultaneously can empty the pool in 9/16 the time than that taken by C alone ⇒ (a + b)/c = 16/9- - - - - - - - - - - - - - - (i) Pipe A, working alone, takes one third the time taken by pipe B ⇒ a/b = 3- - - - - - - - - - - - - - - (ii) 2hr 24min = 2 + 24/60 hr = 2 + 2/5 hour = 12/5 hr Together they can empty the pool in 12/5 hr ⇒ (a + b + c) × 12/5 = 1[Using (ii)] ⇒ (a + a/3 + (a + b) × 9/16) × 12/5 = 1[Using (i)] ⇒ (a + a/3 + (a + a/3) × 9/16) × 12/5 = 1[Using (ii)] ⇒ (a + a/3 + 4a/3 × 9/16) × 12/5 = 1 ⇒ (a + a/3 + 3a/4) = 5/12 ⇒ a(12 + 4 + 9)/12 = 5/12 ⇒ a = 1/5 Since the efficiency of pipe A is a, the time taken by A alone = 1/a = 5 hours |
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| 303. |
A and B can do a work in 45 days and 40 days respectively. They began the work together but A left after some time and B completed the remaining work in 23 days. After how many days of the start of the work did A leave ?1). 10 days2). 9 days3). 8 days4). 5 days |
| Answer» 9 DAYS is the BEST SUITED | |
| 304. |
30 men can repair a road in 18 days. They are Joined by 6 more workers. Now the road can be repaired in1). 14 days2). 15 days3). 16 days4). 17 days |
| Answer» CORRECT ANSWER is: OPTION 2 | |
| 305. |
5 men can do a piece of work in 12 days and 10 women can do the same work in 15 days. 5 men and 10 women undertook the same work for Rs. 36,000. They finished the work in 5 days with the help of 15 children. What is the share of 5 children?1). Rs. 5,0002). Rs. 4,0003). Rs. 3,0004). Rs. 6,000 |
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Answer» Time TAKEN by 5 men to do a piece of work = 12 days ∴ Work done by 5 men in 1 DAY = 1/12 Time taken by 10 women to do the same work = 15 days ∴ Work done by 10 women in 1 day = 1/15 With the help of 15 children they finished the work = 5 days ∴ Work done by (5 men + 10 women + 15 children) in 1 day = 1/5 So, work by 15 children in 1 day = 1/5 - 1/12 - 1/15 = 1/20 Time taken by 15 children to do the same work = 20 days The RATIO of their time = 12 : 15 : 20 We know, the EFFICIENCY is inversely proportional to the time So, ratio of their efficiency = 1/12 : 1/15 : 1/20 = 5 : 4 : 3 So, 5 + 4 + 3 = 12 unit = 36,000 ⇒ 1 unit = 3,000 ⇒ 3 unit = 9,000 ∴ Share of 15 children is 9,000 So, share of 1 child = 9,000/15 = 600 So, share of 5 children = 600 × 5 = 3,000 |
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| 306. |
A and B were assigned to do a job for an amount of Rs. 1,200. A alone can do it in 15 days, while B can do it in 12 days. With the help of C, they can finish in 5 days. The share of amount that C earns is1). Rs. 3002). Rs. 4003). Rs. 5004). Rs. 600 |
| Answer» RS. 300 | |
| 307. |
A and B together can do a piece of work in 12 days which B and C together can do in 16 days. After A has been working at it for 5 days and B for 7 days, C finishes it in 13 days. In how many days B could finish the work ?1). 48 days2). 24 days3). 16 days4). 12 days |
| Answer» 48 DAYS is the CORRECT ANSWER as PER the ssc answer key | |
| 308. |
Two labourers A and B are paid a total of Rs. 650 per day. If A is paid 160 percent of what is paid to B, how much (in Rs.) is B paid?1). 2502). 4003). 3504). 450 |
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Answer» Let A get RS. X and B get Rs. (650 - X) WAGES of A = 160% of wages of B X = 160/100 × (650 - X) ⇒ 10X = 16 × 650 - 16X ⇒ X = 16 × 650/26 = 400 ∴ Wages of B = 650 - 400 = Rs. 250 |
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| 309. |
Aman alone can do a piece of work in 6 days and Bijoy alone in 8 days. Aman and Bijoy undertook to do it for Rs. 3200. With the help of Chinmesh, they completed the work in 3 days. Compute the money to be paid to Chinmesh?1). Rs. 7502). Rs. 6003). Rs. 4004). Rs. 800 |
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Answer» LET Aman, Bijoy and Chinmesh be A, B, and C respectively. C's 1 day's WORK = 1/3 – (1/6 + 1/8) = 1/24 A's WAGES : B's wages : C's wages = 1/6 : 1/8 : 1/24 = 4 : 3 : 1 C's share (for 3 days) = 1/8 × 3200 = Rs. 400 |
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| 310. |
A 10 hectare field is reaped by 2 men. 3 women and 4 children together in 10 days. If working capabilities of a man. a woman and a child are in the ratio 5:4:2. then a 16 hectare field will be reaped by 6 men,4 women and 7 children in1). 5 days2). 6 days3). 7 days4). 8 days |
| Answer» CORRECT ANSWER is: 8 DAYS | |
| 311. |
Samsung and Motorola companies together can manufacture 32 Cell phones in 4 days. After 8 days, Motorola Stopped manufacturing. Samsung took 12 more days to manufacture rest of the cell phones. If total of 100 cell phones were manufactured, the time taken by Motorola to manufacture 15 Cell phones is1). 1 day2). 2 days3). 3 days4). 4 days |
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Answer» It’s Given SAMSUNG and Motorola companies together can manufacture 32 Cell PHONES in 4 days ∴ both can manufacture (32/4) = 8 Cell phones in 1 day. ⇒ Amount of cell phones manufactured in 8 days = 64 cell phones Total cell phones manufactured = 100 Amount LEFT = 100 – 64 = 36 ⇒ Samsung TOOK 12 days to manufacture 36 ∴ It manufactured 3 Cell phones in 1 day. Since in 1 day both can manufacture 8 Cell phones and out of which Samsung can manufacture 3 per day. ⇒ Motorola can manufacture 8 – 3 = 5 cell phones/day. To manufacture 15 set Motorola will need 15/5 = 3 days. |
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