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A contractor undertook to do a piece of work in 12 days. He employed certain number of labours, about 3 of them being absent from the very first day, the rest could finish the work in 18 days. Find the number of men originally employed?1). 152). 63). 134). 9 |
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Answer» Let X be the NUMBER of LABOURS employed initially and Y be the work done by each labour in one day But as 3 of the labours absent and the work was done by the remaining in 18 days Hence the work done initially by X labours in 12 days will be equal to the work done after the 3 labours are gone. ⇒ 12XY = 18(X - 3) Y ⇒ 12X = 18X - 54 ⇒ 6X = 54 ∴ X = 9 |
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