InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
A, B, C can finish a work in 8 hours, 9 hours and 12 hours respectively. They all started working together, but A left 3 hours before completion, B left 4 hours before completion and C continued the work till end. The work is finished in:1). 5.3 hours2). 5.7 hours3). 6.8 hours4). 7.1 hours |
|
Answer» A’s 1 hour work = 1/8 B’s1 hour work = 1/9 C’s 1 hour work = 1/12 Let the work is completed in ‘x’ hours. A worked for (x – 3) hours. B worked for (x – 4) hours. C worked for x hours. Thus, we have, (x – 3)/8 + (x – 4)/9 + x/12 = 1 ⇒ 9(x – 3) + 8(x – 4) + 6X = 72 ⇒ 9x – 27 + 8X – 32 + 6x = 72 ⇒ 23x = 131 ∴ x = 131/23 = 5.7 hours. |
|
| 52. |
A can finish a work in 30 days working 16 hours a day. B can finish the same work in (80/3) days working 18 hours a day. Find in how many days A and B together can finish the same work, if A and B work 20 hours a day?1). 2 days2). 8 days3). 4 days4). 12 days |
| Answer» | |
| 53. |
1). 82). 103). 124). 15 |
|
Answer» Let the number of MEN who agreed to do the work in 20 days be x ⇒ work DONE by x men = 20x Also given (x - 5) men will complete the work in 40 days ⇒ work done by (x - 5) men = 40(x - 5) SINCE the work done by both are same ⇒ 20x = 40(x - 5) ⇒ 20x - 40X = - 200 ⇒ x = 10 ∴ No of men who had agreed to do the work originally = 10 |
|
| 54. |
Ram and Shyam undertook a work for Rs. 5600. Ram alone can do the work in 5 days and Shyam alone can do the work in 9 days. If they work together, then what will be the difference (in Rs.) in the amount they receive?1). 18002). 24003). 22004). 1600 |
|
Answer» Ram’s one day work = (1/5), Shyam’s one day work = (1/9) Ram and Shyam will divide the wages in the RATIO of their one day’s work = (1/5) : (1/9) = 9 : 5 Amount received by Ram = [9/(9 + 5) × 5600] = [9/14 × 5600] = RS. 3600 Amount received by Shyam = [5/(9 + 5) × 5600] = [5/14 × 5600] = Rs. 2000 DIFFERENCE in the amount = Rs. (3600 - 2000) = Rs. 1600 ∴ Required difference = Rs. 1600 |
|
| 55. |
12 persons can do a piece of work in 4 days. How many persons are required to complete 8 times the work in half the time ?1). 1922). 1903). 1804). 144 |
| Answer» | |
| 56. |
1). 54 days2). 57 days3). 60 days4). 63 days |
|
Answer» Let the number of days in which B finishes the work be ‘d’ days Given, A is twice as EFFICIENT as B ∴ Number of days in whicha A finishes the work = d/2 Given, together they can do a work in 21 days In 1 DAY, they together finish 1/21th of the work ∴ 1/d + 2/d = 1/21 ⇒ 3/d = 1/21 ⇒ d = 63 days |
|
| 57. |
A alone can do a piece of work in 20 days and B alone in 30 days. They begin to work together. They will finish half of the work in :1). 8 days2). 9 days3). 12 days4). 6 days |
| Answer» | |
| 58. |
1). 52). 103). 124). 15 |
|
Answer» Given, 4/5th of a CISTERN is filled in 20 MINUTES. Let the capacity of cistern = x ⇒ 4/5th of x = 20 minutes ⇒ x = 25 Remaining part = (1 - 4/5) = 1/5 ⇒ 1/5 of x = 25/5 = 5 minutes |
|
| 59. |
A can do a piece of work in 20 days. He worked for 4 days and B finished the remaining work in 28 days. B alone can do the whole work in how many days?1). 282). 323). 354). 42 |
|
Answer» Let, B can do the work in = x days ∴ 1 day’s work of B = 1/x A can do a piece of work in = 20 days ∴ 1 day’s work of A = 1/20 According to PROBLEM, $( \Rightarrow \frac{4}{{20}} + \frac{{28}}{x} = 1)$ $( \Rightarrow \frac{{4X + 560}}{{20x}} = 1)$ ⇒ 20x = 4x + 560 ⇒ 16X = 560 ⇒ x = 35 ∴ B alone can do the whole work in = 35 days |
|
| 60. |
A farmer can plough a field working 6 hours per day in 18 days. The worker has to work how many hours per day to finish the same work in 12 days ?1). 7 hrs2). 9 hrs3). 11 hrs4). 13 hrs |
| Answer» OPTION 2 is the RIGHT ANSWER | |
| 61. |
In a class, two teachers Mr. Verma and Mr. Singh teach mathematics to the students. Mr. Verma alone can complete course in 16 weeks and Mr. Singh alone in 24 weeks. Starting with Mr. Verma, they take classes on alternate weeks. The entire course will be completed in1). 17 weeks2). 18 weeks3). 19 weeks4). 20 weeks |
|
Answer» Mr. Verma and Mr. Singh COMPLETED 1/16 and 1/24 of the course per week. In two weeks 1/16 + 1/24 = 5/48 of the course will be completed. ∴ In 9 × 2 weeks, 9 × (5/48) of the course will be completed or in 18 weeks, 15/16 of the course will be completed. Remaining course = 1/16 of the course will be completed in 19th week by Mr. Verma. |
|
| 62. |
Three taps A, B and C can fill a tank in 12 hours, 15 hours and 20 hours respectively. If all the taps are opened at 12 PM, then at what time (in PM) should the tap A and C be closed to fill the tank completely at exactly 9 PM?1). 62). 43). 34). 7 |
|
Answer» From 12 PM to 9 PM = 9 hours So, tap B will work = 9 hours Let tap C and A works x hours According to the question ⇒ x/12 + 9/15 + x/20 = 1 ⇒ (5x + 36 + 3X)/60 = 1 ⇒ 8x = 60 - 36 = 24 ⇒ x = 3 hours So, 12 pm + 3 h = 3 pm |
|
| 63. |
P and Q can do a project in 25 and 50 days respectively. In how many days can they complete 18% of the project if they work together?1). 6 days2). 3 days3). 12 days4). 9 days |
|
Answer» <P>⇒ One - DAY work of P = 1/25 ⇒ One - day work of Q = 1/50 ⇒ One - day work of both P and Q together = 1/25 + 1/50 = 3/50 ⇒ Time taken for 18% work = (18/100) × (50/3) = 3 days |
|
| 64. |
Some masons promised to do a work in 10 days but 8 of them were absent and remaining did the work in 18 days. What was the original number of masons?1). 102). 213). 154). 18 |
|
Answer» Time taken = 10 days Now, as 8 masons were ABSENT so, Number of masons = (x - 8) Time taken = 18 Now, as work done is equal ⇒ x × 10 = (x - 8) × 18 ⇒ 10x = 18x - 144 ⇒ 8X = 144 ⇒ x = 18 ∴ original number of masons = 18 |
|
| 65. |
X is 3 times as fast as Y and is able to complete the work in 40 days less than Y. Then the time in which they can complete the work together is1). 15 days2). 10 days3). \(7\frac{1}{2}days\)4). 5 days |
|
Answer» Let X can complete the work alone in X’ days then according to question: Time taken by Y to complete the work alone = 3X’ Given, X can complete the work in 40 days less than Y. Then, ⇒ X’ = 3X’ – 40 ⇒ X’ = 20 Thus, X can complete the work alone in 20days while Y can do it alone in 60 days. Let the total work be denoted by W units. Then, PORTION of work done by X alone in 1 day = W/20 Also, portion of work done by Y alone in 1 day = W/60 Let them together complete the work in D days. Then, $(\RIGHTARROW \LEFT( {\frac{W}{{20}} + \frac{W}{{60}}} \right) \times D = W)$ ⇒ D = 15 days Hence X and Y both can complete work in 15 days. |
|
| 66. |
1). 11/2 months2). 4 months3). 9 months4). 9/2 months |
| Answer» | |
| 67. |
Two inlet pipes can fill a cistern in 20 and 24 hours respectively and an outlet pipe can empty 160 gallons of water per hour. All the three pipes working together can fill the empty cistern in 40 hours. What is the capacity (in gallons) of the tank?1). 12002). 24003). 36004). 1800 |
|
Answer» Let outlet pipe can empty the tank in x hrs. Given that, $(\begin{array}{l}\frac{1}{{20}} + \frac{1}{{24}} - \frac{1}{{\RM{x}}} = \frac{1}{{40}}\\\frac{1}{x} = \frac{1}{{20}} + \frac{1}{{24}} - \frac{1}{{40}} = \frac{{6 + 5 - 3}}{{120}} = \frac{1}{{15}}\END{array})$ Outlet pipe can empty the tank in 15 hrs. Given that, Outlet pipe can empty 160 GALLONS of water per hour. ⇒ Total capacity of the tank = 160?15 = 2400 gallons |
|
| 68. |
In a garrison, there was food for 1000 soldiers for one month. By what per cent the food supplies should be increased so that total 1200 soldiers could last with the new supplies?1). 20%2). 40%3). 80%4). 120% |
|
Answer» Food needed for 1000 SOLDIERS for ONE month = 1000 × 1 units Food needed for 1200 soldiers for one month = 1200 × 1 units Percentage INCREASE = (1200 - 1000)/1000 × 100 = 20% |
|
| 69. |
1). 122). 103). 144). 13 |
| Answer» | |
| 70. |
1). 182). 243). 124). 21 |
|
Answer» Given, P can do a piece of work in 36 days. Q is 50% more ef?cient than P then, Ratios of TIME TAKEN by P and Q is = Let Q alone can do same work in a days. ⇒ 3 / 2 = 36 / a ⇒ a = (36 × 2) / 3 ⇒ a = 24 ∴ In 24 days Q can do same work. |
|
| 71. |
If 16 men or 20 women can do a piece of work in 25 days. In what dme will 28 men and 15 women do it?1). $14\frac{2}{7}$ days2). $33\frac{1}{3}$ days3). $18\frac{3}{4}$ days4). 10 days |
|
Answer» it from previous year ssc papers, 10 DAYS is the right ANSWER |
|
| 72. |
A group experiment was conducted. If 2 students of Class 12 and 1 student of class 11 can complete the experiment in 14 minutes while 4 students of class 11 and 2 students of class 12 can complete it in 8 minutes. If one Class 12 student gets Rs. 600 for doing the experiment, how much should a class 11 student get?1). Rs. 9002). Rs. 2003). Rs. 3004). Rs. 400 |
|
Answer» Assume it takes x minutes for a class 12 student to complete the experiment. So His rate of work per MINUTE will be 1/x. Similarly for class 11 student let it be y minutes therefore rate per minute will be 1/y. ⇒ 2/x + 1/y = 1/14 ⇒ 4/y + 2/x = 1/8 ⇒ 28/x + 14/y = 1 ⇒ 32/y + 16/x = 1 Multiply both SIDES by xy 28y + 14x = xy 32x + 16Y = xy ⇒ 28y + 14x = 32x + 16y 12y = 18x ⇒ y = 3x/2 There for a class 11 student should get 2/3 × 600 = Rs. 400 |
|
| 73. |
A and B together can complete a work in 8 days. B alone can complete that worked for four days, After that how long will A alone take to complete the work ?1). 15 days2). 18 days3). 16 days4). 20 days |
| Answer» 16 DAYS SEEMS CORRECT. | |
| 74. |
4 mat-weavers can weave 4 mats in 4 days. At the same rate how many mats would be woven by 8 mat-weavers in 8 days ?1). 42). 83). 124). 16 |
| Answer» CORRECT ANSWER is: 16 | |
| 75. |
1). 10002). 7503). 5004). 250 |
|
Answer» Initially number of employee = X After 20 days number of employee = x + 500 According to Question, 30 × x = [(20 × x) + {(x + 500) × 5}] 30x = 20X + 5x + 2500 30x – 25X = 2500 5x = 2500 x = 500 |
|
| 76. |
A can do a piece of work in 4 hours; B and C can do it in 3 hours, A and C can do it in 2 hours. How long will B alone take to do it ?1). 10 hours2). 12 hours3). 8 hours4). 24 hours |
| Answer» RIGHT ANSWER for this QUESTION is 12 HOURS | |
| 77. |
A work could be completed in 100 days by some workers. However, due to the absence of 10 workers, it was completed in 110 days.The original number of workers was :1). 1002). 1103). 554). 50 |
| Answer» 110 is the ANSWER | |
| 78. |
Both X and Y together can complete a work in 12 days and Y alone can complete the same work in 30 days. In how many days will X alone complete the work?1). 152). 203). 184). 16 |
|
Answer» X and Y TOGETHER can complete a WORK = 12 days Y ALONE can complete the same work = 30 Let X alone can complete the same work = x days ⇒ 1/x + 1/30 = 1/12 ⇒ 1/x = 1/12 - 1/30 ⇒ 1/x = (30 - 12)/(30 × 12) ∴ x = 20 days |
|
| 79. |
A contractor undertook to finish a certain work in 124 days and employed 120 men . After 64 days , he found that he had already done $\frac{2}{3}$ of the work. How many men can be dis- charged now so that the work may finish in time ?1). 482). 563). 404). 50 |
| Answer» 56 : SEEMS CORRECT | |
| 80. |
Three men A, B and C working together can do a Job in 6 hours less time than A alone, in 1 hour less time than B alone and in one half the time needed by C when working alone.Then A and B together can do the Job in1). $\frac{2}{3}$ hour2). $\frac{3}{4}$ hour3). $\frac{3}{2}$ hour4). $\frac{4}{3}$ hour |
| Answer» OPTION 4 is the CORRECT ANSWER as per the answer key | |
| 81. |
A contractor undertakes to make a road in 40 days and employs 25 men. After 24 days, he finds that only one-third of the road is made. How many extra men should he employ so that he is able to complete the work 4 days earlier ?1). 1002). 603). 754). None of these |
| Answer» | |
| 82. |
If x men can do a piece of work in x days, then the number of days in which y men can do the same work is1). xy days2). $\frac{y^{2}}{x}$ days3). $\frac{x^{2}}{y}$ days4). $x^{2}y$ days |
| Answer» | |
| 83. |
A certain number of persons can complete a piece of work in 55 days. If there were 6 persons more, the work could be finished in 11 days less. How, many persons were originally there ?1). 172). 243). 304). 22 |
| Answer» ANSWER for this QUESTION is OPTION 2 | |
| 84. |
A tank can be filled by two taps X and Y in 5 hrs and 10 hrs respectively while another tap Z empties the tank in 20 hrs. In how many hours can be tank be filled, if all 3 taps are kept open?1). 52). 43). 74). 8 |
|
Answer» EFFICIENCY of X = 1/5 Efficiency of Y = 1/10 Efficiency of Z = 1/20 ⇒ Total efficiency of X, Y and Z = (1/5) + (1/10) - (1/20) = 1/4 ∴ Total time TAKEN is 4 hours |
|
| 85. |
1). 202). 253). 164). 15 |
|
Answer» B’s 1 day work = 1/50 Together with C, they did the work in 6.25 days A’s 1 day work + B’s 1 day work + C’s 1 day work = 1/6.25 = 4/25 ⇒ C’s 1 day work = 4/25 - 1/10 - 1/50 = 4/25 - 3/25 = 1/25 ∴ C can alone do the JOB in 25 days |
|
| 86. |
Two pipes P and Q can fill the tank alone in 60 and 90 hours respectively. If they are opened together, then in how many hours will the tank be filled?1). 352). 323). 364). 30 |
|
Answer» PART of tank filled by P in 1 hour = 1/60 Part of tank filled by Q in 1 hour = 1/90 ⇒ Part of tank filled by both in 1 hour = 1/60 + 1/90 = (3 + 2)/180 = 5/180 ∴ TIME taken by both to fill the tank = 180/5 = 36 HOURS |
|
| 87. |
A, B and C can complete a work in 20, 24 and 30 days respectively. All three of them starts together but after 4 days A leaves the job and B left the job 6 days before the work was completed. C completed the remaining work alone. In how many days was the total work completed?1). 102). 123). 144). 16 |
|
Answer» LET the total amount of work be X Work done by A is one day = X/20 Work done by B in one day = X/24 Work done by C in one day = X/30 A, B and C work together for 4 days, Work finished in four days = 4 × ((X/20) + (X/24) + (X/30)) = 4 × (6 + 5 + 4) × X / 120 This give the work finished in first four days = (1/2) × X B left the job 6 days before the work was finished, so C worked alone for 6 days Work done by C in 6 days is = 6 × X / 30 = X/5 Work done by (X/2) + (X/5) = (7 × X)/10 Work left = X - (7/10) × X = (3/10) × X This work is finished by B and C working together The work done by B and C in one day is = (X/24) + (X/30) = (9/120) × X Let B and C together work for N days then N × (9/120) × X = (3/10) × X This means N = 4 ∴ Total number of days = 4 + 4 + 6 = 14 |
|
| 88. |
A can do a certain work in 12 days. B is 60% more efficient than A. How many days will B and A together take to do the same job ?1). $\frac{80}{13}$ days2). $\frac{70}{13}$ days3). $\frac{75}{13}$ days4). $\frac{60}{13}$ days |
| Answer» | |
| 89. |
R is 80% more efficient than S. If S alone can make a book in 90 days, then R alone can make the book in how many days?1). 652). 603). 504). 70 |
|
Answer» Let efficiency of S be 100 Thus, Efficiency of R = 100 × 180/100 = 180 Ratio of their efficiency R : S = 180 : 100 = 9 : 5 If S alone can make a book in 90 DAYS, So, Total work = 90 × 5 = 450 ∴ R alone can COMPLETE the book = 450/9 = 50 days |
|
| 90. |
A man and a woman working together can do a certain work in 18 days. Their skills in doing the work are in the ratio 3:2. many days will the woman take to finish the work alone?1). 45 days2). 36 days3). 27 days4). 30 days |
| Answer» 45 DAYS is the BEST SUITED | |
| 91. |
1). \(100\frac{6}{7}\) days2). 110 days3). 102 days4). 104 days |
| Answer» | |
| 92. |
5 men can do a piece of work in 6 days while 10 women can do it in 5 days. In how many days can 5 women and 3 men do it ?1). 4 days2). 5 days3). 6 days4). 8 days |
|
Answer» it from PREVIOUS year ssc PAPERS, option 2 is the right ANSWER |
|
| 93. |
If two persons, with equal abilities, can do two Jobs in two days, then 100 persons with equal abilities can do 100 similar Jobs in1). 100 days2). 10 days3). 5 days4). 2 days |
| Answer» | |
| 94. |
Quantity B: Two persons A and B can finish a piece of work in 12 days. If A works thrice its efficiency and B works half of its efficiency then the work will be finished in 8 days. Find the time in which A will complete thrice the work alone.1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
|
Answer» Quantity A: Suppose the efficiencies of P, Q and R is p, q and r respectively Given that P & R together can finish the work in HALF the time Q can finish it ⇒ Efficiency of P & R together will be twice the efficiency of Q ⇒ (p + r) ? q = 2 ? 1 = 8 ? 4 (Let) P & Q together are thrice efficient than R ⇒ (p + q) ? r = 3 ? 1 = 9 ? 3 ⇒ p ? q ? r = 5 ? 4 ? 3 Since P, Q and R working together can complete the work in 30 days ⇒ Total UNITS of work = 12 × 30 = 360 units ⇒ Time taken by Q to complete the work = 360/4 = 90 days Quantity B: Suppose the efficiencies of A and B are ‘a’ and ‘b’ respectively According to the given statements : ⇒ 12(a + b) = 8(3a + b/2) ⇒ 12a + 12b = 24a + 4b ⇒ 12a = 8b ⇒ a ? b = 2 ? 3 Since A and B can finish the work in 12 days ⇒ Total units of work = 5× 12 = 60 units ⇒ Time taken by A to complete thrice the work = 3 × 60/2 = 90 days ∴ Quantity A = Quantity B |
|
| 95. |
A can do one and a half as much of a work which B can do in one day. B alone can do a piece of work in 18 days. They together can finish that work in1). $10\frac{1}{5}$ days2). $11\frac{1}{5}$ days3). $5\frac{1}{5}$ days4). $7\frac{1}{5}$ days |
| Answer» OPTION 4 : SEEMS CORRECT | |
| 96. |
A can do a piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in1). 5 days2). 7 days3). 11 days4). 3 days |
| Answer» | |
| 97. |
1). 102). 63). 124). 5 |
|
Answer» Let the work last for x days. Then, A WORKED for (x - 2) days and B for x days. Now, $(\FRAC{{x - 2}}{8} + \frac{x}{{12}} = 1)$ x = 6 days. |
|
| 98. |
Twenty women together can complete a work in 16 days, 16 men together can complete the same work in 15 days. The ratio of the working capacity of a men to that of a women is :1). 3:42). 4:33). 5:34). 4:5 |
| Answer» OPTION 2 : 4:3 is CORRECT | |
| 99. |
A and B together do a job in 15 days and A alone could do the same job in 20 days. How many days would B take to do half the job if he worked alone?1). 602). 303). 454). 40 |
|
Answer» Work done by A in 1 day can be given as 1/20th of the total work Let the work done by B in 1 day be y of the total work From the PROBLEM statement ⇒ 15 × (1/20 + y) = 1 ⇒ y = 1/15 - 1/20 = 1/60 Time required by B to complete the work is 60 DAYS Time required to complete the half work is ½ × 60 = 30 days ∴ The time required to complete half of the work is 30 days |
|
| 100. |
A and B undertook to do a piece of work for Rs. 4500. A alone could do it in 8 days and B alone in 12 days. With the assistance of C they finished the work in 4 days. Then C's share of the money is1). Rs. 22502). Rs. 15003). RS. 7504). Rs. 375 |
| Answer» RIGHT ANSWER is RS. 750 | |