1.

A can do a piece of work in 20 days. He worked for 4 days and B finished the remaining work in 28 days. B alone can do the whole work in how many days?1). 282). 323). 354). 42

Answer»

Let, B can do the work in = x days

∴ 1 day’s work of B = 1/x

A can do a piece of work in = 20 days

∴ 1 day’s work of A = 1/20

According to PROBLEM,

$( \Rightarrow \frac{4}{{20}} + \frac{{28}}{x} = 1)$ 

$( \Rightarrow \frac{{4X + 560}}{{20x}} = 1)$ 

⇒ 20x = 4x + 560

16X = 560

⇒ x = 35

∴ B alone can do the whole work in = 35 days



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