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A can do a piece of work in 20 days. He worked for 4 days and B finished the remaining work in 28 days. B alone can do the whole work in how many days?1). 282). 323). 354). 42 |
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Answer» Let, B can do the work in = x days ∴ 1 day’s work of B = 1/x A can do a piece of work in = 20 days ∴ 1 day’s work of A = 1/20 According to PROBLEM, $( \Rightarrow \frac{4}{{20}} + \frac{{28}}{x} = 1)$ $( \Rightarrow \frac{{4X + 560}}{{20x}} = 1)$ ⇒ 20x = 4x + 560 ⇒ 16X = 560 ⇒ x = 35 ∴ B alone can do the whole work in = 35 days |
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