1.

Some masons promised to do a work in 10 days but 8 of them were absent and remaining did the work in 18 days. What was the original number of masons?1). 102). 213). 154). 18

Answer»

LET the NUMBER of MASONS be x

Time taken = 10 days

Now, as 8 masons were ABSENT so,

Number of masons = (x - 8)

Time taken = 18

Now, as work done is equal

⇒ x × 10 = (x - 8) × 18

⇒ 10x = 18x - 144

8X = 144

⇒ x = 18

∴ original number of masons = 18


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