A and B are two metals with threshold frequencies `1.8 xx 10^(14)Hz` and `2.2 xx 10^(14)Hz`. Two identical photons of energy 0.825 eV each are incident on them. Then, photoelectrons are emitted by (Taking, `h = 6.6 xx 10^(-34)J-s`)

A and B are two metals with threshold frequencies `1.8 xx 10^(14)Hz` a

1.	A and B are two metals with threshold frequencies `1.8 xx 10^(14)Hz` and `2.2 xx 10^(14)Hz`. Two identical photons of energy 0.825 eV each are incident on them. Then, photoelectrons are emitted by (Taking, `h = 6.6 xx 10^(-34)J-s`)
Answer» Correct Answer - B Threshold energy of A is `E_(A)=hv_(A)` `=6.6xx10^(-34)xx1.8 xx10^(14)` `11.88xx10^(-20)J` `=(11.88xx10^(-20))/(1.6 xx 10^(-19))eV` `=0.74 eV` Similarl, `E_(B) = 0.91 eV` Since, the incident photons have energy greater than `E_(A)` but less than `E_(B)`. So, photoelectrons will be emitted from metal A only.

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A and B are two metals with threshold frequencies `1.8 xx 10^(14)Hz` and `2.2 xx 10^(14)Hz`. Two identical photons of energy 0.825 eV each are incident on them. Then, photoelectrons are emitted by (Taking, `h = 6.6 xx 10^(-34)J-s`)

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