The voltage applied to an electron microscope to produce electrons of wavelength `0.50 Å` isA. 602 VB. 50 VC. 138 VD. 812 V

The voltage applied to an electron microscope to produce electrons of

1.	The voltage applied to an electron microscope to produce electrons of wavelength `0.50 Å` isA. 602 VB. 50 VC. 138 VD. 812 V
Answer» Correct Answer - A de-Broglie wavelength is `lambda=(h)/(mv)=(h)/(sqrt(2mE))` `"But "E=ev` `lambda=(h)/(sqrt(2meV))implies V=(h^(2))/(2melambda^(2))` `V=((6.62 xx 10^(-34))^(2))/((0.5xx10^(-10))^(2)xx2xx9.1xx10^(-31)xx1.6xx10^(-19))` `impliesV=601.98V=602V`

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The voltage applied to an electron microscope to produce electrons of wavelength `0.50 Å` isA. 602 VB. 50 VC. 138 VD. 812 V

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