If `n_(r )` and `n_(b)` are the number of photons of red and blue light respectively with same energy, thenA. `n_(r ) gt n_(b)`B. `n_(r ) lt n_(b)`C. `n_(r ) = n_(b)`D. no relation between `n_(r )` and `n_(b)`

If `n_(r )` and `n_(b)` are the number of photons of red and blue ligh

1.	If `n_(r )` and `n_(b)` are the number of photons of red and blue light respectively with same energy, thenA. `n_(r ) gt n_(b)`B. `n_(r ) lt n_(b)`C. `n_(r ) = n_(b)`D. no relation between `n_(r )` and `n_(b)`
Answer» Correct Answer - A `("VIBGYOR")/(lambda"(increases)")E=n.(hc)/(lambda)` From equation, `" "E_(r )=E_(b)" (Given)"` `" or "n_(r ).(hc)/(lambda_(r ))=n_(b).(hc)/(lambda_(b))" or "(n_(r ))/(lambda_(b))=(lambda_(r))/(lambda_(b))because(lambda_(r ))/(lambda_(b))gt1` Hence, `(n_(r ))/(n_(b))gt1" or "n_(r )gt n_(b)`

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If `n_(r )` and `n_(b)` are the number of photons of red and blue light respectively with same energy, thenA. `n_(r ) gt n_(b)`B. `n_(r ) lt n_(b)`C. `n_(r ) = n_(b)`D. no relation between `n_(r )` and `n_(b)`

If `n_(r )` and `n_(b)` are the number of photons of red and blue light respectively with same energy, thenA. `n_(r ) gt n_(b)`B. `n_(r ) lt n_(b)`C. `n_(r ) = n_(b)`D. no relation between `n_(r )` and `n_(b)`

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