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A and B are two mutually exclusive and exhaustive events of a random experiment such that `P(A)=6[P(B)]^2` where P(A) and P(B) denotes probability of A and B respectively. Find P(A) and P(B) |
Answer» As, `A` and `B` are mutually exahaustive events, `:. A uu B = S` `:.P(AuuB) = P(S) = 1` As, `A` and `B` are mutually exclusive events, `:. P(AuuB) = P(A)+P(B)`. `=>P(A)+P(B) = 1` `=>6P(B)^2+P(B) - 1 = 0`...(Given that `P(A) = 6P(B)^2`) `=>6P(B)^2+3P(B)-2P(B) - 1 = 0` `=>3P(B)(2P(B)+1)-1(2P(B)+1) = 0` `=>(3P(B)-1)(2P(B)+1) = 0` `=>P(B) = 1/3 and P(B) = -1/2` As, `P(B)` can not be negative, so, `P(B) = 1/3` `:. P(A) = 6(1/3)^2 = 2/3.` |
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