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A And B Can Do A Piece Of Work In 30 Days, While B And C Can Do The Same Work In 24 Days And C And A In 20 Days. They All Work Together For 10 Days When B And C Leave. How Many Days More Will A Take To Finish The Work ? |
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Answer» (A & B)'s 1 day work = 1/30 (B & C)'s 1 day work = 1/24 (C & A)'s 1 day work = 1/20 so 2 (A + B + C)'s 1 day's work = (1/30+1/24+1/20) = 15/120 = 1/8 => (A + B + C)'s 1 day's work = 1/16 Work done by A, B and C in 10 days = (10*1/16) = 5/8 so LEFT work = (1?5/8)=3/8 A's 1 day's work (1/16?1/24)=1/48 => 1/48 part of work is done by A = 1 day. So, 3/8 part of work will be done by A = (48?3/8) = 6*3 = 18 days. (A & B)'s 1 day work = 1/30 (B & C)'s 1 day work = 1/24 (C & A)'s 1 day work = 1/20 so 2 (A + B + C)'s 1 day's work = (1/30+1/24+1/20) = 15/120 = 1/8 => (A + B + C)'s 1 day's work = 1/16 Work done by A, B and C in 10 days = (10*1/16) = 5/8 so left work = (1?5/8)=3/8 A's 1 day's work (1/16?1/24)=1/48 => 1/48 part of work is done by A = 1 day. So, 3/8 part of work will be done by A = (48?3/8) = 6*3 = 18 days. |
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