Saved Bookmarks
| 1. |
A And B Can Do A Piece Of Work In 45 Days And 40 Days Respectively. They Began To Do The Work Together But A Leaves After Some Days And Then B Completed The Remaining Work In 23 Days. The Number Of Days After Which A Left The Work Was? |
|
Answer» A's 1 DAY work = 1/45 B's 1 day work = 1/40 so (A + B)'s 1 day's work = (1/45+1/40)=17/360 Work DONE by B in 23 days = (140? 23) =2340 Remaining work = (1-23/40) =17/40 Now, 17/360 work was done by (A + B) = 1 day. 17/40 PART of work was done by (A + B) = (1? 360/17? 17/40) = 9 days. A LEFT after 9 days. A's 1 day work = 1/45 B's 1 day work = 1/40 so (A + B)'s 1 day's work = (1/45+1/40)=17/360 Work done by B in 23 days = (140? 23) =2340 Remaining work = (1-23/40) =17/40 Now, 17/360 work was done by (A + B) = 1 day. 17/40 part of work was done by (A + B) = (1? 360/17? 17/40) = 9 days. A left after 9 days. |
|