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A Can Contains A Mixture Of Two Liquids A And B Is The Ratio 7: 5. When 9 Litres Of Mixture Are Drawn Off And The Can Is Filled With B, The Ratio Of A And B Becomes 7: 9. How Many Litres Of Liquid A Were Contained By The Can Initially? |
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Answer» Suppose the can initially CONTAINS 7x and 5 xs of mixtures A and B respectively. QUANTITY of A in mixture LEFT = (7x-7*9/12) Litres = (7x - 21/4) litres. Quantity of B in mixture left = (5x - 5*9/12) Litres = (5x - 15/4) litres. [(7x - 21/4)/ (5x-15/4) +9] = 7/9 => (28x - 21)/ (20X + 21) = 7/9 => 252x - 189 = 140x + 147 => 112x = 336 => x = 3. So, can contained 21 litres of A. Suppose the can initially contains 7x and 5 xs of mixtures A and B respectively. Quantity of A in mixture left = (7x-7*9/12) Litres = (7x - 21/4) litres. Quantity of B in mixture left = (5x - 5*9/12) Litres = (5x - 15/4) litres. [(7x - 21/4)/ (5x-15/4) +9] = 7/9 => (28x - 21)/ (20x + 21) = 7/9 => 252x - 189 = 140x + 147 => 112x = 336 => x = 3. So, can contained 21 litres of A. |
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