It Takes 8 Hours For A 600 Km Journey, If 120 Km Is Done By Train And

1.	It Takes 8 Hours For A 600 Km Journey, If 120 Km Is Done By Train And The Rest By Car. It Takes 20 Minutes More, If 200 Km Is Done By Train And The Rest By Car. The Ratio Of The Speed Of The Train To That Of The Cars Is?
Answer» Assume Here the speed of the train = X km/hr and speed of car = y km/hr. GIVEN FIRST journey information: (120/x + 480/y) = 8 => (120/x + 480/y)/8 = 1 (15/x + 60/y) = 1 => (1/x + 4/y) = 1/15 ---------- (1) Given Second journey information: And, (200/x + 400/y) = 25 => (1/x + 2/y) = 25/200 ------- (2) By SOLVING (1) and (2) x = 60 and y = 80. So Ratio of speeds = 60: 80 = 3: 4 Assume Here the speed of the train = x km/hr and speed of car = y km/hr. Given First journey information: (120/x + 480/y) = 8 => (120/x + 480/y)/8 = 1 (15/x + 60/y) = 1 => (1/x + 4/y) = 1/15 ---------- (1) Given Second journey information: And, (200/x + 400/y) = 25 => (1/x + 2/y) = 25/200 ------- (2) By Solving (1) and (2) x = 60 and y = 80. So Ratio of speeds = 60: 80 = 3: 4

It Takes 8 Hours For A 600 Km Journey, If 120 Km Is Done By Train And The Rest By Car. It Takes 20 Minutes More, If 200 Km Is Done By Train And The Rest By Car. The Ratio Of The Speed Of The Train To That Of The Cars Is?

Answer»

Assume Here the speed of the train = X km/hr

and speed of car = y km/hr.

GIVEN FIRST journey information:

(120/x + 480/y) = 8 => (120/x + 480/y)/8 = 1

(15/x + 60/y) = 1 => (1/x + 4/y) = 1/15 ---------- (1)

Given Second journey information:

And, (200/x + 400/y) = 25 => (1/x + 2/y) = 25/200 ------- (2)

By SOLVING (1) and (2)

x = 60 and y = 80.

So Ratio of speeds = 60: 80

= 3: 4

Assume Here the speed of the train = x km/hr