1.

A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work?

Answer»

40 DAYS



Let 1 MAN's 1 day's work = X and 1 woman's 1 day's work = y.

Then, 4x + 6y = 1/8 and 3x + 7y = 1/10 .

Solving the TWO equations, we get: x = 11/400 , y = 1/400

1 woman's 1 day's work = 1/400 .

10 WOMEN's 1 day's work = 1/400 x 10 = 1/40 .

Hence, 10 women will complete the work in 40 days.



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