1.

A can do a piece of work in 14 days which B alone can do in 21 days. They begin together but 3 days before the completion of the work, A leaves off. The total number of days for the work to be complet

Answer»

10 1/5 days



B’s 1 day’s WORK = 1/21
B’s 3 day’s work = 1/21 ×3 = 1/7 
The remaining work FINISHED by both of them = 1 – 1/7 = 6/7 
Both together can finish it in 14 × 21/35 days = 42/5 days 
Their, 1 day’s work = 5/42 
Therefore, the No. of days TAKEN by them together to finish 6/7 work 



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