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A And B Run A 5 Km Race On A Round Course Of 400 M. If Their Speed Be In The Ratio 5 : 4, How Often Does The Winner Pass The Other On Circular Track? |
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Answer» Total no. of round will be 5000/400 = 12.5 No. of rounds A COMPLETES to finish the race will be 12.5 and by the time B can complete only 10 rounds. (As ratio of SPEED of A & B is 5: 4. So they meet for the first time after A has finished 5 rounds and B has finished 4 rounds.) So difference in no. of round will be = 21⁄2 The winner MEETS the other 2 times because the winner meets the other after EVERY 2000 meters. Total no. of round will be 5000/400 = 12.5 No. of rounds A completes to finish the race will be 12.5 and by the time B can complete only 10 rounds. (As ratio of speed of A & B is 5: 4. So they meet for the first time after A has finished 5 rounds and B has finished 4 rounds.) So difference in no. of round will be = 21⁄2 The winner meets the other 2 times because the winner meets the other after every 2000 meters. |
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