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A And B Together Can Do A Piece Of Work In 12 Days, Which B And C Together Can Do In 16 Days. After A Has Been Working At It For 5 Days And B For 7 Days, C Finishes It In 13 Days. In How Many Days C Alone Will Do The Work? |
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Answer» (A and B) 1 day work = 1/12 -----(1) (B and C) 1 day work = 1/16 -----(2) GIVEN A's 5 days' work + B's 7 days' work + C's 13 days' work = 1 Simplify the above... => (A + B)'s 5 days' work + (B + C)'s 2 days' work + C's 11 days' work = 1 Put the values from EQUATION (1) & (2) => (5*1/12)+(2*1/16) + C's 11 days' work = 1 => C's 11 days' work = (1-5/12+2/16)=11/24 => C's 1 day's work = (11/24? 1/11) =1/24 So C alone can FINISH the work = 24 days. (A and B) 1 day work = 1/12 -----(1) (B and C) 1 day work = 1/16 -----(2) Given A's 5 days' work + B's 7 days' work + C's 13 days' work = 1 Simplify the above... => (A + B)'s 5 days' work + (B + C)'s 2 days' work + C's 11 days' work = 1 Put the values from equation (1) & (2) => (5*1/12)+(2*1/16) + C's 11 days' work = 1 => C's 11 days' work = (1-5/12+2/16)=11/24 => C's 1 day's work = (11/24? 1/11) =1/24 So C alone can finish the work = 24 days. |
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