A bag contains 2 red. 3 green and 2 blue balls, Two balls are drawn at

1.	A bag contains 2 red. 3 green and 2 blue balls, Two balls are drawn at random. What is the probability that none of the balls drawn is blue?1. 2/72. 11/213. 10/214. 5/7
Answer» Correct Answer - Option 3 : 10/21 Given: A bag contains 2 red 3 green and 2 blue balls, Two balls are drawn at random. Formula Used: Probability = favorable outcome/total outcome Calculation: None of the balls drawn is blue, this can only happen when the two balls drawn at random are either red and green or both. Total number of balls = 2 + 3 + 2 = 7 ⇒ Number of ways of drawing 2 balls out of 7 = ⁷C₂ = (7 × 6) / (2 × 1) = 42/2 = 21 Number of balls other than blue = 5 ⇒ Number of ways of drawing 2 balls out of 5 = ⁵C₂ = (5 × 4) / (2 × 1) = 20/2 = 10 ∴ Required Probability = 10/21

A bag contains 2 red. 3 green and 2 blue balls, Two balls are drawn at random. What is the probability that none of the balls drawn is blue?1. 2/72. 11/213. 10/214. 5/7

Answer» Correct Answer - Option 3 : 10/21

Given:

A bag contains 2 red 3 green and 2 blue balls, Two balls are drawn at random.

Formula Used:

Probability = favorable outcome/total outcome

Calculation:

None of the balls drawn is blue, this can only happen when the two balls drawn at random are either red and green or both.

Total number of balls = 2 + 3 + 2 = 7

⇒ Number of ways of drawing 2 balls out of 7 = ⁷C₂ = (7 × 6) / (2 × 1) = 42/2 = 21

Number of balls other than blue = 5

⇒ Number of ways of drawing 2 balls out of 5 = ⁵C₂ = (5 × 4) / (2 × 1) = 20/2 = 10

∴ Required Probability = 10/21

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