1.

A Ball Dropped From H Height And Moves 80% Of Height Each Time. Total Distance Covered Is?

Answer»

First time distance= H

Second time = 80H/100 = 4H/5

similarly THIRD time 80% of 4H/5 = H(4^2)/(5^2)

and so on.. 

This will lead to infinite terms of geometric progression

i.e H+2*4H/5+2*16H/25..

So, Sum = H+ 2*4H/(5(1-4/5)) = 9H.

First time distance= H

Second time = 80H/100 = 4H/5

similarly third time 80% of 4H/5 = H(4^2)/(5^2)

and so on.. 

This will lead to infinite terms of geometric progression

i.e H+2*4H/5+2*16H/25..

So, Sum = H+ 2*4H/(5(1-4/5)) = 9H.


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