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Which Of The Following Numbers Are Completely Divisible By 11? |
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Answer» If the difference of the sum of digits at odd places and the sum of its digits at even places, is either 0 or divisible by 11, then CLEARLY the number is divisible by 11. [(Sum of digits at odd places) - (Sum of digits at even places)]/11 => [(3+4+6+2) - (2+5+8)]/11 => (15 - 15)/11 = 0/11 = 0 similarly others number are divisible by 11. If the difference of the sum of digits at odd places and the sum of its digits at even places, is either 0 or divisible by 11, then clearly the number is divisible by 11. [(Sum of digits at odd places) - (Sum of digits at even places)]/11 => [(3+4+6+2) - (2+5+8)]/11 => (15 - 15)/11 = 0/11 = 0 similarly others number are divisible by 11. |
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