1.

In A Stream Running At 2 Kmph,a Motar Boat Goes 6 Km Upstream And Back Again To The Starting Point In 33 Minutes. Find The Speed Of The Motarboat In Still Water?

Answer»

Lets assume speed of boat in still water = x km/hr

So boat downstream speed = (x+2) km/hr.

boat upstream speed = (x-2) km/hr.

6/(x-2)+6/(x+2)=33/60 => 6/(x-2)+6/(x+2)=11/20

=> 120*[(x-2) + (x+2)] = 11*x^2 -44

=> 240 x = 11*x^2-44

=> 11* x^2 -240x -44 = 0 ---------(1)

By solving EQ. (1) 

x = 22 km/hr.

Lets assume speed of boat in still water = x km/hr

So boat downstream speed = (x+2) km/hr.

boat upstream speed = (x-2) km/hr.

6/(x-2)+6/(x+2)=33/60 => 6/(x-2)+6/(x+2)=11/20

=> 120*[(x-2) + (x+2)] = 11*x^2 -44

=> 240 x = 11*x^2-44

=> 11* x^2 -240x -44 = 0 ---------(1)

By solving eq. (1) 

x = 22 km/hr.


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