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A ball having mass 500g hits wall with a 10m/s velocity. Wall applies 4000 N force to the ball and it turns back with 8m/s velocity. Find the time of ball-wall contact. |
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Answer» Initial momentum=MV= 1/2*10=5kgm/s Final= m(-V)= -mv= -1/2(8)= -4kgm/s Δmomentum=final-initial = -4 - 5 = -9kgm/s F= Δmomentum/Δtime Δtime=Δmomentum/F =9/4000 SECONDS. Hence t= 9/4000= 2.25*10⁻³ seconds |
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