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A ball is dropped from a height of 10 m. If energy of the ballreduces by 40% after striking the ground, how high can the ballbounce back? (g 10 ms-) |
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Answer» The potential energy at height of 10m =mgh =m×10×10 =100m(jule) On sticking the ground,the potential energy get converted into kinetic energy Kinetic energy=100J Energy is reduced by 40% so the remaining energy=60%×100 =60J The height upto which the ball can bounce back is given by 'h' such that mgh=60m×10×h=60×mh=60/10h=6m thanks |
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