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A ball is dropped from the top of a building 100 m high. At the same instant another ball is thrown upwards with a velocity of `40ms^(-1)` form the bottom of the building. The two balls will meet after.A. 5 sB. 2.5 sC. 2 sD. 3 s |
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Answer» Correct Answer - B `t=(d_(r))/(v_(r))=(h)/(u_(1)+u_(2))[because a_(r)=0],u_(1)=0` |
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