A ball is gently dropped from a height of 20m.If its velocity increase

1.	A ball is gently dropped from a height of 20m.If its velocity increase uniformly at the rate of 10m/s, with what velocity will it strike the ground? After what time will it strike the ground?
Answer» $\huge\star{\underline{\mathtt{\red{A}\pink{n}\green{s}\blue{w}\purple{e}\orange{r}}}}$ Given:- Initial velocity of ball(u) = 0 Final velocity of ball (v) = ? Distance through which ball falls (s) = 20m Acceleration (a) = 10m/s Time of fall (t) = ? We know, ${v}^{2} - {u}^{2} = 2as$ ${v}^{2} = ( {u)}^{2} + 2as$ ${v}^{2} = ( {0)}^{2} + 2 \times 10 \times 20$ ${v}^{2} = 400$ $v = \sqrt{400} = 20$ $v = 20 {ms}^{2}$ we know that, v = u + at = 20 = 0 +10 × t = 10 t = 20 t = 28