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A ball is initially moving with a velocity 0.5 m s^(-1) ms. Its velocity decreases at a rate of 0.05 m s^(-2). (a) How much time will it take to stop ? (b) How much distance will the ball travel before it stops ? |
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Answer» SOLUTION :GIVEN, initial velocity u = 0.5 m `s^(-1)`, final velocity v = 0, acceleration a = - 0-05 m `s^(-2)`? (Here negative sign is used since velocity decreases with time). (a) From equation of motion v = u + at `0= 0.5 - 0.05 xxt` or 0.05 t = 0.5 or `t = (0.5)/(0.05)` = 10 s (b) From equation of motion `v^(2)= u^(2)+ 2A S ` `0 =(0.5)^(2)- 2 xx0.05 XXS ` or `0.1 S = 0.5 ` or S `= (0.25)/(0.1)= 2.5 ` m |
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