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A ball is projected vertically upwards with a certain initial speed. Another ball of the same mass is projected at an angle of `60^(@)` with the vertical with the same initial speed. At highest points of their journey, the ratio of their potential energies will beA. `1:1`B. `2:1`C. `3:2`D. `4:1` |
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Answer» Correct Answer - D In verticle upwards. PE=mgh `=mg((V_(2))/(2g))=(mv^(2))/(2)`...(i) at an angle of `60^(@)` with vertical PE=mgh `=mg((V^(2)sin^(2)30^(@))/(2g))=(mv^(2))/(8)`....(ii) From (i)/(ii). `((PE)_(up))/((PE)_("at" theta=60^(@)"fromvt.))=((mv^(2))/(2))/((mv^(2))/(8))=(4)/(1)` |
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