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A ball is projected vertically upwards with a velocity of `25ms^(-1)` from the bottom of a tower. A boy who is standing at the top of a tower is unable to catch the ball when it passes him in the upward direction. But the ball again reaches him after 3 sec when it is falling. Now the boy catches it then the height of the tower is `(g=10ms^(-2))`A. 5mB. 10 mC. 15 mD. 20 m |
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Answer» Correct Answer - D `t=(2v)/(g),v^(2)u^(2)=-2gh` |
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