1.

A ball is released from a height and it reaches the ground in 3s. if g=9.8m s-2 ,find:(a) The height from which the ball was released,(b) The velocity with which the ball will strike the ground.

Answer»

Given, t = 3 sec

u = 0 m/s

a = G = 9.8m/s²

V = u + at

v = 0 + 9.8(3)

v = 29.4 m/s

v² - u² = 2as

(29.4)² - 0 = 2(9.8)s

s = (29.4)²/19.6

s = 44.1 m

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