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A ball is released from a height and it reaches the ground in 3s. if g=9.8m s-2 ,find:(a) The height from which the ball was released,(b) The velocity with which the ball will strike the ground. |
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Answer» Given, t = 3 sec u = 0 m/s a = G = 9.8m/s² V = u + at v = 0 + 9.8(3) v = 29.4 m/s v² - u² = 2as (29.4)² - 0 = 2(9.8)s s = (29.4)²/19.6 s = 44.1 m plz MARK it as brainliest b..bye #ANSWERWITHQUALITY #BAL |
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