1.

.A ball is thrown vertically upward with a velocity of 49 m/s.The maximum height to which it can rise is ​

Answer»

Answer:

122.5 m

Explanation:

Given Initial velocity of ball, U=49 m/s

Let the maximum height reached and time taken to reach that height be H and t respectively.

Assumption: g=9.8 m/s       holds true (maximum height reached is small compared to the radius of earth)

Velocity of the ball at maximum height is zero, v=0

Given Initial velocity of ball, u=49 m/s

Let the maximum height reached and time taken to reach that height be H and t respectively.

Assumption: g=9.8 m/s  

2

 holds true (maximum height reached is small compared to the radius of earth)

Velocity of the ball at maximum height is zero, v=0

v^2 - u^2 = 2aH

0 - (49)^2 = 2*(-9.8)*H

⟹H=122.5 m  

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