1.

a ball is thrown vertically upwards. it reaches a height h and comes back to it's initial position. calculate distance travelled and displacement of the ball​

Answer»

Answer:

(a):(u)^2/g

(b):0

Explanation:

s MAX=(u)^2/2g

total DISTANCE travelled by the stone is twice the max. HEIGHT attained.

so,distance is (u)^2/g.

since the initial and final POINTS are the same THUS the net displacement is 0.



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