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a ball is thrown vertically upwards. it reaches a height h and comes back to it's initial position. calculate distance travelled and displacement of the ball |
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Answer» Answer: (a):(u)^2/g (b):0 Explanation: s MAX=(u)^2/2g total DISTANCE travelled by the stone is twice the max. HEIGHT attained. so,distance is (u)^2/g. since the initial and final POINTS are the same THUS the net displacement is 0. |
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