1.

A ball is thrown vertically upwards. It returns6 s later. Calculate : fit the greatest height reachedby the ball, and if the initial velocity of the ball,(Take g = 10 m s^)

Answer»

TIME taken for maximum height=6/2=3s

we KNOW

v=u+at

0=u+ (-10)3

u=30m/s

and

s = ut + 1 \div 2at {}^{2}  \\  \:  \:  = \: 30 \times 3 + 1 \div 2 \times 10 \times 3 \\   \:  \:  \:  = 105m

I hope it is helpful for u



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