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A ball is thrown vertically upwards witha a velocity of 48 m/s. Calculate |
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Answer» Given parameters Initial VELOCITY of the ball (u) = 49m/s. The velocity of the ball at maximum height (v) = 0. g = 9.8m/s2 Let US considered the time taken is t to reach the maximum height H. 2gH = v2 – u2 2 × (- 9.8) × H = 0 – (49)2 – 19.6 H = – 2401 H = 122.5 m Now consider a formula, v = u + g × t 0 = 49 + (- 9.8) × t – 49 = – 9.8t t = 5 sec |
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