1.

A ball is thrown vertically upwards witha a velocity of 48 m/s. Calculate​

Answer»

Given parameters

Initial VELOCITY of the ball (u) = 49m/s.

The velocity of the ball at maximum height (v) = 0.

g = 9.8m/s2

Let US considered the time taken is t to reach the maximum height H.

CONSIDER a FORMULA,

2gH = v2 – u2

2 × (- 9.8) × H = 0 – (49)2

– 19.6 H = – 2401

H = 122.5 m

Now consider a formula,

v = u + g × t

0 = 49 + (- 9.8) × t

– 49 = – 9.8t

t = 5 sec



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